y=(2x^2-20x)/25

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Solution for y=(2x^2-20x)/25 equation:


x in (-oo:+oo)

y = (2*x^2-(20*x))/25 // - (2*x^2-(20*x))/25

y-((2*x^2-(20*x))/25) = 0

y-((2*x^2-20*x)/25) = 0

(-1*(2*x^2-20*x))/25+y = 0

(-1*(2*x^2-20*x))/25+(25*y)/25 = 0

25*y-1*(2*x^2-20*x) = 0

20*x-2*x^2+25*y = 0

(20*x-2*x^2+25*y)/25 = 0

(20*x-2*x^2+25*y)/25 = 0 // * 25

20*x-2*x^2+25*y = 0

20*x-2*x^2+25*y = 0

DELTA = 20^2-(-2*4*25*y)

DELTA = 200*y+400

200*y+400 = 0

200*y+400 = 0 // - 400

200*y = -400 // : 200

y = -400/200

y = -2

DELTA = 0 <=> t_3 = -2

x = -20/(-2*2) i y = -2

x = 5 i y = -2

( x = ((200*y+400)^(1/2)-20)/(-2*2) or x = (-(200*y+400)^(1/2)-20)/(-2*2) ) i y > -2

( x = ((200*y+400)^(1/2)-20)/(-4) or x = ((200*y+400)^(1/2)+20)/4 ) i y > -2

y+2 > 0

y+2 > 0 // - 2

y > -2

x in { 5, ((200*y+400)^(1/2)-20)/(-4), ((200*y+400)^(1/2)+20)/4 }

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